Generalized Cayley-Bacharach theorem

Generalized Cayley-Bacharach theorem

In this post I will showcase a generalization of the famous 8 implies 9 theorem also known as Cayley-Bacharach. I will work over \mathbb{C}. The exposition is due to David Eisenbud, Mark Green, and Joe Harris in the paper “CAYLEY-BACHARACH THEOREMS AND CONJECTURES” posted in BULLETIN (New Series) of the american mathematical society (Volume 33, Number 3, July 1996). The original article can be found by a google search.

Main theorem. Let X_1,X_2\subset \mathbb{P}^2 be plane curves of degree d and e, respectively, intersecting in d\cdot e points \Gamma=X_1\cap X_2=\{p_1,\hdots,p_{de}\}, and suppose that \Gamma is the disjoint union of subsets \Gamma' and \Gamma''. Let s=d+e-3. If k\leq s is a nonnegative integer, then the dimension of the vector space of homogeneous polynomials of degree k vanishing on \Gamma' (modulo those containing all of \Gamma) is equal to the failure of \Gamma'' to impose independent conditions on homogeneous polynomials of degree s-k.

Proof. See the article referenced.

Explaining the terminology. Suppose we have three distinct colinear points \Gamma=\{p_1,p_2,p_3\}. Then the failure of \Gamma to impose independent conditions on polynomials of degree 1 is equal to 3-2=1, as a degree 1 polynomial is a line which are determined by two points. In general, if \Gamma\subset \mathbb{P}^2 is a finite set of points and \lambda\in\mathbb{N}\cup\{0\} is minimal such that \lambda of the \vert \Gamma\vert conditions suffices to imply all of them, we say that \Gamma imposes \lambda independent conditions on polynomials of degree \leq m. The failure of \Gamma to impose independent conditions of is the number \vert\Gamma\vert-\lambda.

If we let k=s and \Gamma''=\{p_{de}\}, then we find

Corollary. Let X_1,X_2\subset\mathbb{P}^2 be plane curves of degree d and e, respectively, intersecting in d\cdot e points \Gamma=X_1\cap X_2=\{p_1,\hdots,p_{de}\}. If C\subset\mathbb{P}^2 is any plane curve of degree s=d+e-3 containing all but one point of \Gamma, then C contains all of \Gamma.

Proof. Setting k=s=d+e-3 and \Gamma''=\{p_{de}\} in the main theorem, we readily see that the dimension of homogeneous polynomials of degree d+e-3 vanishing on \Gamma'=\{p_1,\hdots,p_{de-1}\} is equal to the failure of \Gamma''=\{p_{de}\} to impose independent conditions on homogeneous polynomials of degree 0. The latter being equal to 0. Thus we conclude that there are no homogeneous polynomials of degree d+e-3 containing \Gamma' except these containing \Gamma (this is the interpretation of the “modulo those containing all of \Gamma” in the main theorem).

If we set d=e=3, we recover the classical Cayley-Bacharach theorem:

Theorem (Cayley-Bacharach). Let X_1,X_2\subset\mathbb{P}^2 be cubic curves intersecting in 3\cdot 3=9 points \Gamma=X_1\cap X_2=\{p_1,\hdots,p_{9}\}. If C\subset\mathbb{P}^2 is any cubic curve containing eight of the nine points, then it also contains the last point.

“Application” Let us apply the main theorem to a problem from euclidian geometry. In the following diagram, we are asked to show that the red points lie on a circle:

Solution. We redefine by assuming the red points lie on a circle, and then prove that the last red point lie on a line as shown in the diagram below. Let X_1 be the union of the three circles and X_2 be the union of the four green lines and the line at infinity. These curves have degree 2+2+2=6 and 1+1+1+1+1=5, respectively. As the three circles all pass through the imaginary circle points at infinity, I and J, we must count these two points trice thrice when taking the intersection

    \begin{align*}\Gamma=X_1\cap X_2&=\{\text{The 16 real points in the picture}\}\\&\cup\{3 \text{ times }I, 3 \text{ times }J\}\\&\cup \{\text{the 4 (complex) intersections of the big circle with the two inner most green lines}\}\\&\cup\{\text{the 4 (complex) intersections of the pink circle with the two outer most green lines}\}\end{align*}

Now, let \Gamma' be the latter eight points in the intersection and \Gamma'' the other 22 points. Pick k=3\leq 8=6+5-3=s. Now, as there’s always a cubic passing through 8 given points, we see that the dimension of the vector space of homogeneous polynomials of degree k=3 vanshing on \Gamma' (modulo those containing all of \Gamma) is nonzero. Thus the failure of \Gamma'' to impose independent conditions on homogeneous polynomials of degree s-k=8-3=5 is nonzero. In particular, a degree 5 curve passing through 21 of the 22 points of \Gamma' must pass through the last point. So we finish by taking C as the union of the four black lines and the line at infinity.

Thank you for reading.

1 Comment

  1. Jacob

    Very informative and well written

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